(3x^2+4x-5)/(x+2)

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Solution for (3x^2+4x-5)/(x+2) equation: 


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

(3*x^2+4*x-5)/(x+2) = 0

3*x^2+4*x-5 = 0

3*x^2+4*x-5 = 0

DELTA = 4^2-(-5*3*4)

DELTA = 76

DELTA > 0

x = (76^(1/2)-4)/(2*3) or x = (-76^(1/2)-4)/(2*3)

x = (2*19^(1/2)-4)/6 or x = (-2*19^(1/2)-4)/6

(x-((-2*19^(1/2)-4)/6))*(x-((2*19^(1/2)-4)/6)) = 0

((x-((-2*19^(1/2)-4)/6))*(x-((2*19^(1/2)-4)/6)))/(x+2) = 0

( x-((-2*19^(1/2)-4)/6) )

x-((-2*19^(1/2)-4)/6) = 0 // + (-2*19^(1/2)-4)/6

x = (-2*19^(1/2)-4)/6

( x-((2*19^(1/2)-4)/6) )

x-((2*19^(1/2)-4)/6) = 0 // + (2*19^(1/2)-4)/6

x = (2*19^(1/2)-4)/6

x in { (-2*19^(1/2)-4)/6, (2*19^(1/2)-4)/6 }

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